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Allow node to cluster edges

pull/438/head
Bruno Meneguello 3 anos atrás
committed by tessier
pai
commit
7bd3078255
1 arquivos alterados com 23 adições e 6 exclusões
  1. +23
    -6
      diagrams/__init__.py

+ 23
- 6
diagrams/__init__.py Ver arquivo

@@ -185,7 +185,9 @@ class Diagram(_Cluster):

self.dot = Digraph(self.name, filename=self.filename)
self._nodes = {}
self._edges = {}

self.dot.attr(compound="true")
# Set attributes.
self.dot.attr(compound="true")
for k, v in self._default_graph_attrs.items():
@@ -225,6 +227,17 @@ class Diagram(_Cluster):
for nodeid, node in self._nodes.items():
self.dot.node(nodeid, label=node['label'], **node['attrs'])

for nodes, edge in self._edges.items():
node1, node2 = nodes
nodeid1, nodeid2 = node1.nodeid, node2.nodeid
if hasattr(node1, '_nodes') and node1._nodes:
edge._attrs['ltail'] = nodeid1
nodeid1 = next(iter(node1._nodes.keys()))
if hasattr(node2, '_nodes') and node2._nodes:
edge._attrs['lhead'] = nodeid2
nodeid2 = next(iter(node2._nodes.keys()))
self.dot.edge(nodeid1, nodeid2, **edge.attrs)

self.render()
# Remove the graphviz file leaving only the image.
os.remove(self.filename)
@@ -255,7 +268,11 @@ class Diagram(_Cluster):

def connect(self, node: "Node", node2: "Node", edge: "Edge") -> None:
"""Connect the two Nodes."""
self.edges[(node, node2)] = edge
self._edges[(node, node2)] = edge

def subgraph(self, dot: Digraph) -> None:
"""Create a subgraph for clustering"""
self.dot.subgraph(dot)

def render(self) -> None:
self.dot.render(format=self.outformat, view=self.show, quiet=True)
@@ -469,16 +486,16 @@ class Node:
self._diagram.node(self._id, self.label, **self._attrs)

def __enter__(self):
setcluster(self)
self.name = "cluster_" + self.label
self.dot = Digraph(self.name)
self._nodes = {}

if self._cluster:
self._cluster.remove_node(self._id)
else:
self._diagram.remove_node(self._id)

setcluster(self)
self._id = "cluster_" + self.label
self.dot = Digraph(self._id)
self._nodes = {}

# Set attributes.
for k, v in self._default_graph_attrs.items():
self.dot.graph_attr[k] = v


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